(2x^2+18x+39)/x-6

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Solution for (2x^2+18x+39)/x-6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x^2+18*x+39)/x-6 = 0

(2*x^2+18*x+39)/x+(-6*x)/x = 0

2*x^2+18*x-6*x+39 = 0

2*x^2+12*x+39 = 0

2*x^2+12*x+39 = 0

2*x^2+12*x+39 = 0

DELTA = 12^2-(2*4*39)

DELTA = -168

DELTA < 0

1 = 0

1/x = 0

1/x = 0 // * x

1 = 0

x belongs to the empty set

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